HackerRank Python If-Else problem solution | python Questions Solutions

Task
Given an integer, , perform the following conditional actions:

If  is odd, print Weird

If  is even and in the inclusive range of  to , print  Not Weird

If  is even and in the inclusive range of  to , print Weird

If  is even and greater than , print  Not Weird

Input Format

A single line containing a positive integer, .

Constraints

 

Output Format

Print Weird if the number is weird. Otherwise, print Not Weird.

Sample Input 0

3

Sample Output 0

Weird

Explanation 0

 is odd and odd numbers are weird, so print Weird.

Sample Input 1

24

Sample Output 1

Not Weird

Explanation 1

 and  is even, so it is not weird.

 

Problem solution in Python 2 programming.

#!/bin/python

import sys


N = int(raw_input().strip())

if (N%2):
    print ("Weird")
elif (N>=2 and N<=5):
    print ("Not Weird")
elif (N>=6 and N<=20):
    print ("Weird")
else: print ("Not Weird")

Problem solution in Python 3 programming.

#!/bin/python3

import math
import os
import random
import re
import sys



if __name__ == '__main__':
    n = int(input().strip())

    if n%2 != 0:
        print("Weird")
    else:
        if n>=2 and n<=5:
            print("Not Weird")
        elif n>=6 and n<=20:
            print("Weird")
        else:
            print("Not Weird")

Problem solution in pypy programming.   

# Enter your code here. Read input from STDIN. Print output to STDOUT
n = int(raw_input())

if n%2 == 1:
   print('Weird')
elif n>=2 and n<=5:
    print('Not Weird')
elif n>=6 and n<=20:
    print('Weird')
elif n>20: 
    print('Not Weird')

Problem solution in pypy3 programming.

# Enter your code here. Read input from STDIN. Print output to STDOUT
val = int(input())
output = "Weird"
if val%2 == 1:
    pass
elif 2 <= val < 5:
    output = "Not Weird"
elif 6 <= val <= 20:
    pass
else:
    output = "Not Weird"

print(output)