HackerRank Collections.OrderedDict() solution in python | python question solution

collections.OrderedDict

An OrderedDict is a dictionary that remembers the order of the keys that were inserted first. If a new entry overwrites an existing entry, the original insertion position is left unchanged.

Example

Code

>>> from collections import OrderedDict
>>> 
>>> ordinary_dictionary = {}
>>> ordinary_dictionary['a'] = 1
>>> ordinary_dictionary['b'] = 2
>>> ordinary_dictionary['c'] = 3
>>> ordinary_dictionary['d'] = 4
>>> ordinary_dictionary['e'] = 5
>>> 
>>> print ordinary_dictionary
{'a': 1, 'c': 3, 'b': 2, 'e': 5, 'd': 4}
>>> 
>>> ordered_dictionary = OrderedDict()
>>> ordered_dictionary['a'] = 1
>>> ordered_dictionary['b'] = 2
>>> ordered_dictionary['c'] = 3
>>> ordered_dictionary['d'] = 4
>>> ordered_dictionary['e'] = 5
>>> 
>>> print ordered_dictionary
OrderedDict([('a', 1), ('b', 2), ('c', 3), ('d', 4), ('e', 5)])

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Task

You are the manager of a supermarket.
You have a list of  items together with their prices that consumers bought on a particular day.
Your task is to print each item_name and net_price in order of its first occurrence.

item_name = Name of the item.
net_price = Quantity of the item sold multiplied by the price of each item.

Input Format

The first line contains the number of items, .
The next  lines contains the item's name and price, separated by a space.

Constraints

Output Format

Print the item_name and net_price in order of its first occurrence.

Sample Input

9
BANANA FRIES 12
POTATO CHIPS 30
APPLE JUICE 10
CANDY 5
APPLE JUICE 10
CANDY 5
CANDY 5
CANDY 5
POTATO CHIPS 30

Sample Output

BANANA FRIES 12
POTATO CHIPS 60
APPLE JUICE 20
CANDY 20

Explanation

BANANA FRIES: Quantity bought: , Price: 
Net Price: 
POTATO CHIPS: Quantity bought: , Price: 
Net Price: 
APPLE JUICE: Quantity bought: , Price: 
Net Price: 
CANDY: Quantity bought: , Price: 
Net Price: 20

In this Collections.orderedDict() problem we need to develop a python program that can read an integer and string that are separated with a line. and then we need to use the orderedDict() function to store the input and then print the item name and price of that item on the output screen.

Problem solution in Python 2 programming.

from collections import OrderedDict
nTrans = int(raw_input())
inventories = OrderedDict()
for n in range(nTrans):
    tmp = raw_input().split()
    item = ' '.join(tmp[0:len(tmp)-1])
    price = int(tmp[-1])
    if item in inventories:
        inventories[item] += price
    else:
        inventories[item] = price
items = list(inventories.items())
items.sort()
for item in items:
    print item[0], item[1]

Problem solution in Python 3 programming.

# Enter your code here. Read input from STDIN. Print output to STDOUT
from collections import OrderedDict
d = OrderedDict()
for _ in range(int(input())):
    item, space, quantity = input().rpartition(' ')
    d[item] = d.get(item, 0) + int(quantity)
for item, quantity in d.items():
    print(item, quantity)

Problem solution in pypy programming.

# Enter your code here. Read input from STDIN. Print output to STDOUT
from collections import OrderedDict
items = int(raw_input())
items_price = OrderedDict()
for _ in range(items):
    desc = raw_input().split()
    if not items_price.get(" ".join(desc[0:-1]),None):
        items_price[" ".join(desc[0:-1])] =0
    items_price[" ".join(desc[0:-1])] += int(desc[-1])

for i,j in items_price.items():
    print i,j

Problem solution in pypy3 programming.

from collections import OrderedDict

d = OrderedDict()
for _ in range(int(input())):
    info = input().split(' ')
    price = int(info[-1])
    info.pop()
    item = ' '.join(info)
    price = int(price)
    if not item in d:
        d[item] = price
    else:
        d[item] += price

for pair in d:
    print(pair + ' ' + str(d[pair]))